## Are endomorphisms Injective?

In the case of finite-dimensional vector spaces, an endomorphism is injective if and only if it is surjective. In the case of finitely generated modules over a commutative ring, if an endomorphism is surjective, then it is injective.

## What is the difference between endomorphism and automorphism?

Let V be a vector space over a field F. A vector space homomorphism that maps V to itself is called an endomorphism of V . The set of all endomorphisms of V will be denoted by L (V,V ). A vector space isomorphism that maps V to itself is called an automorphism of V .

**What is endomorphism group theory?**

In algebra, an endomorphism of a group, module, ring, vector space, etc. is a homomorphism from one object to itself (with surjectivity not required). In ergodic theory, let be a set, a sigma-algebra on and a probability measure. A map is called an endomorphism (or measure-preserving transformation) if. 1.

**Does Injective implies surjective?**

An injective map between two finite sets with the same cardinality is surjective. An injective linear map between two finite dimensional vector spaces of the same dimension is surjective.

### Are all Endomorphisms linear?

The set of all endomorphisms forms an associative algebra. That is, the set is a linear space with multiplication. This algebra is often denoted by EndF(V) or by L(V,V).

### What is the difference between epimorphism and monomorphism?

In the category of sets, a function f from X to Y is an epimorphism iff (if an only if) it is surjective. Also in the category of sets, a function is a monomorphism iff it is injective. Groups are similar in that a group homomorphism is an epimorphism iff it surjective, and a monomorphism iff it is injective.

**Is every isomorphism an epimorphism?**

Every isomorphism is an epimorphism; indeed only a right-sided inverse is needed: if there exists a morphism j : Y → X such that fj = idY, then f: X → Y is easily seen to be an epimorphism. A map with such a right-sided inverse is called a split epi.

**Is every isomorphism an automorphism?**

The identity is the identity morphism from an object to itself, which is an automorphism. By definition every isomorphism has an inverse that is also an isomorphism, and since the inverse is also an endomorphism of the same object it is an automorphism.

## Is an endomorphism a homomorphism?

Endomorphism. An endomorphism is a homomorphism whose domain equals the codomain, or, more generally, a morphism whose source is equal to its target. The endomorphisms of an algebraic structure, or of an object of a category form a monoid under composition. The endomorphisms of a vector space or of a module form a ring …

## Can a function be surjective but not injective?

(a) Surjective, but not injective One possible answer is f(n) = L n + 1 2 C, where LxC is the floor or “round down” function. So f(1) = f(2) = 1, f(3) = f(4) = 2, f(5) = f(6) = 3, etc. f(3) = f(4) = 4 f(5) = f(6) = 6 and so on. (d) Bijective.

**Can a function be neither injective nor surjective?**

An example of a function which is neither injective, nor surjective, is the constant function f : N → N where f(x) = 1. An example of a function which is both injective and surjective is the iden- tity function f : N → N where f(x) = x.

**What is a ring automorphism?**

In other words, a ring automorphism of a ring is a bijective ring homomorphism from the ring onto itself.

### What is a Surjective homomorphism?

An epimorphism is a surjective homomorphism, that is, a homomorphism which is onto as a mapping. The image of the homomorphism is the whole of H, i.e. im(f) = H. A monomorphism is an injective homomorphism, i.e. a homomorphism where different elements of G are mapped to different elements of H.

### Is the identity map an automorphism?

The identity mapping IS:(S,∘)→(S,∘) on the algebraic structure (S,∘) is an automorphism.

**Do homomorphisms have to be injective?**

For the first direction you can just use the injectivity of the homomorphism and the fact that by definition of a group homomorphism we must have that f(1G)=1H. For the other direction assume that ker(f) is more than just the identity, and that the group homomorphism is injective, then reach a contradiction.

**Can a function be both injective and surjective?**

Alternatively, f is bijective if it is a one-to-one correspondence between those sets, in other words both injective and surjective. Example: The function f(x) = x2 from the set of positive real numbers to positive real numbers is both injective and surjective. Thus it is also bijective.